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Q) Check whether function f(x) defined as f(π‘₯)={((|π‘₯βˆ’3|)/(2(π‘₯βˆ’3)), π‘₯=3 (π‘₯βˆ’6)/6,π‘₯β‰₯3) Is
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Q) Check whether function f(x) defined as f(π‘₯)={((|π‘₯βˆ’3|)/(2(π‘₯βˆ’3)), π‘₯=3 (π‘₯βˆ’6)/6,π‘₯β‰₯3) Is
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YouTubeShivang Maths Academy
Q) Find the domain of sec^(βˆ’1) (2π‘₯+1). #maths #shivangmathsacademy #shivangmathsacademy #cbsemaths
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Q) Find the domain of sec^(βˆ’1) (2π‘₯+1). #maths #shivangmathsacademy #shivangmathsacademy #cbsemaths
3.1K views1 month ago
YouTubeShivang Maths Academy
Q) Evaluate sin[cos^(βˆ’1) cos(7πœ‹/6)] #shivangmathsacademy #cbsemaths #class12maths #maths
1:05
Q) Evaluate sin[cos^(βˆ’1) cos(7πœ‹/6)] #shivangmathsacademy #cbsemaths #class12maths #maths
3.9K views1 month ago
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Find the value of k for which the function 𝐟(𝐱)={((πŸβˆ’πœπ¨π¬π±)/(𝟐𝐱^𝟐 ), 𝐒𝐟 π±β‰ πŸŽ 𝐀, 𝐒𝐟
1:44
Find the value of k for which the function 𝐟(𝐱)={((πŸβˆ’πœπ¨π¬π±)/(𝟐𝐱^𝟐 ), 𝐒𝐟 π±β‰ πŸŽ 𝐀, 𝐒𝐟
1.6K views1 week ago
YouTubeShivang Maths Academy
2:15
JThe number of points of discontinuity f(x) = {(|𝐱|+πŸ‘, 𝐒𝐟 π±β‰€βˆ’πŸ‘ βˆ’πŸπ±, 𝐒𝐟 βˆ’πŸ‘=𝐱=πŸ‘ πŸ”π±+𝟐,
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1:09
Q) If 𝑓(π‘₯)={(3π‘₯βˆ’2, 0≀π‘₯≀1 2π‘₯^2+π‘Žπ‘₯, 1≀π‘₯≀2) is continuous for π‘₯∈(0,2), then a is equal to
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1:23
If 𝑓(π‘₯)={ ((sin^2 π‘Žπ‘₯)/π‘₯^2 if π‘₯β‰ 0 1 , if π‘₯=0) is continuous at π‘₯=0, then the value of ' π‘Ž β€˜
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1:42
Q) Simplify : cot^(βˆ’1) √((1+cos2π‘₯)/(1βˆ’cos2π‘₯)),π‘₯∈(0,πœ‹/2).#maths #cbsemaths #class12 #cbse2026
2.4K views4 weeks ago
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1:01
If a function defined by 𝑓(π‘₯)={(π‘˜π‘₯+1, π‘₯β‰€πœ‹ cosπ‘₯ ,π‘₯=πœ‹) is continuous at π‘₯=πœ‹, then the val
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0:51
Q) Simplify : tan^(βˆ’1) {√((1βˆ’cosπ‘₯)/(1+cosπ‘₯))}}#class12maths #shivangmathsacademy #cbsemaths
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1:46
Q) Find the value of π‘˜, so that 𝑓(π‘₯)={(π‘˜cosπ‘₯/(πœ‹βˆ’2π‘₯), if π‘₯β‰ πœ‹/2@3, if π‘₯=πœ‹/2) is continu
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2:13
Q) If 𝑓(π‘₯)={ ((π‘₯^2βˆ’4π‘₯βˆ’5)/(π‘₯+1), π‘₯β‰ βˆ’1 π‘˜,&π‘₯=βˆ’1 is continuous at π‘₯=βˆ’1, then the value of π‘˜ i
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1:50
Q) The function 𝑓 defined by 𝑓(π‘₯)={ (π‘₯,f π‘₯≀1 5, if π‘₯= 1 is not continuous at(A) x=0(B) π‘₯
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1:53
Q) If 𝑓(π‘₯)={((1βˆ’sin^3 π‘₯)/(3cos^2 π‘₯), for π‘₯β‰ πœ‹/2 π‘˜, for π‘₯=πœ‹/2) is continuous at π‘₯=πœ‹/2, t
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Q) Domain of 𝑠𝑖𝑛^(βˆ’1) (2π‘₯^2βˆ’3) is (A) (βˆ’1,0)βˆͺ(1,√2)(B) (βˆ’βˆš2,βˆ’1)βˆͺ(0,1)(C) [βˆ’βˆš2,βˆ’1]βˆͺ[1,√2](D) (βˆ’
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If 𝑓(π‘₯)={ ((sin^2 π‘Žπ‘₯)/π‘₯^2 if π‘₯β‰ 0 1 , if π‘₯=0) is continuous at π‘₯=0, then the value of ' π‘Ž β€˜
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